# Calculus Question

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[math]int(8x^8 -6) dx[/math]

- [math]8/9x^9+C[/math]
- [math]64x^7+c[/math]
- [math]8/9x^9-6x+C[/math]
- [math]8/9x^9-6+C[/math]

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Find the following indefinite integral

[math]int(8x^8 -6) dx[/math]

[math]int(8x^8 -6) dx[/math]

- [math]8/9x^9+C[/math]
- [math]64x^7+c[/math]
- [math]8/9x^9-6x+C[/math]
- [math]8/9x^9-6+C[/math]

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