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Common Core Standard HSG-GPE.A.1 Questions

Derive the equation of a circle of given center and radius using the Pythagorean Theorem; complete the square to find the center and radius of a circle given by an equation.

You can create printable tests and worksheets from these questions on Common Core standard HSG-GPE.A.1! Select one or more questions using the checkboxes above each question. Then click the add selected questions to a test button before moving to another page.

Grade 12 Circles CCSS: HSG-GPE.A.1
What is the equation for a circle with center [math](2,5)[/math] and radius of 5?
  1. [math](x+2)^2+(y+5)^2=25[/math]
  2. [math](x-2)^2+(y-5)^2=5[/math]
  3. [math](x+2)^2+(y+5)^2=5[/math]
  4. [math](x-2)^2+(y-5)^2=25[/math]
Grade 12 Circles CCSS: HSG-GPE.A.1
What is the equation for a circle with center [math](2,-2)[/math] and radius of 2?
  1. [math](x-2)^2+(y+2)^2=4[/math]
  2. [math](x-2)^2+(y+2)^2=2[/math]
  3. [math](x+2)^2+(y-2)^2=2[/math]
  4. [math](x+2)^2+(y-2)^2=4[/math]
Grade 12 Circles CCSS: HSG-GPE.A.1
What is the equation for a circle with center [math](-2,-2)[/math] and the outer point of the radius at [math](7,10)[/math]?
  1. [math](x-2)^2+(y-2)^2=100[/math]
  2. [math](x+2)^2+(y+2)^2=225[/math]
  3. [math](x-2)^2+(y-2)^2=289[/math]
  4. [math](x+2)^2+(y+2)^2=149[/math]
Grade 12 Circles CCSS: HSG-GPE.A.1
What is the equation for a circle with center [math](1,-4)[/math] and the outer point of the radius at [math](-3,-5)[/math]?
  1. [math](x-1)^2+(y+4)^2=15[/math]
  2. [math](x+1)^2+(y-4)^2=15[/math]
  3. [math](x-1)^2+(y+4)^2=17[/math]
  4. [math](x-1)^2+(y+4)^2=289[/math]

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