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 Grade 12 :: Calculus by jthompson85
 $f(x) = [(2x+4)/(3x-1)]^3$ $f'(x) = 3[(2x+4)/(3x-1)]^2[((3x-1)(2) -(2x+4)(3))/(3x-1)^2]$
 Grade 12 :: Calculus by cvenable34
 Find the limit:$lim(2x^2)/(3x^2+5)$ as $xrarroo$ 2/3
 Grade 12 :: Calculus by jthompson85
 $f(x) = 5sin(x^2+1)$ $f'(x) = 5cos(x^2+1)(2x)$
 Grade 12 :: Calculus by jthompson85
 $f(x) = sqrt (9x^2 +4)$ $f'(x) = (18x)/(2(sqrt(9x^2 + 4)$
 Grade 12 :: Calculus by jthompson85
 $f(x) = sqrt tan(3x)$ $f'(x) =1/(2(sqrttan(3x)))(sec^2(3x))(3)$
 Grade 12 :: Calculus by jthompson85
 $f(x) = sec(9x^2)$ $f'(x) = sec(9x^2)tan(9x^2)(18x)$
 Grade 12 :: Calculus by ew609980
 $int x^2/(x^3+5) dx$ $1/3 ln(x^3+5)$
 Grade 12 :: Calculus by jthompson85
 $f(x) = ln(3x^2 + 9x + 4)$ $f'(x) = 1/(3x^2+9x+4)(6x+9)$
 Grade 12 :: Calculus by cvenable34
 Find the limit:$lim(5cosx)/x$ as $xrarroo$ 0
 Grade 12 :: Calculus by cvenable34
 Use the First Derivative Test to find any relative extrema of the function:$h(t)=1/4t^4-8t$ Minimum (2, -12)
 Grade 12 :: Calculus by cvenable34
 Can the Mean Value Theorem be applied to the function $f(x)=1/x^2$on the interval [-2, 1]? Explain why or why not. No. There is a nonremovable discontinuity for f(x) in that interval.
 Grade 12 :: Calculus by skweckwerth
 Grade 12 :: Calculus by skweckwerth
 Grade 12 :: Calculus by cvenable34
 Find the critical numbers (if any) and the open intervals on which the function is increasing or decreasing:$h(x)=sqrt(x)(x-3), x>0$ Critical number: x=1Increasing (-â, 1), (7/3, â)Decreasing (1, 7/3)
 Grade 12 :: Calculus by jthompson85
 $f(x)=2^cosx$ $f'(x) = 2^cosx ln (2) (-sinx)$
 Grade 12 :: Calculus by skweckwerth
 Grade 12 :: Calculus by cvenable34
 Determine the points of inflection of the function:$f(x)=x+cosx, [0,2pi]$ (Ï/2, Ï/2), (3Ï/2, 3Ï/2)
 Grade 12 :: Calculus by cvenable34
 Find the point(s) guaranteed by the Mean Value Theorem for the closed interval given:$f(x)=x^(2/3), [1,8]$ f'(2744/729)=3/7
 Grade 12 :: Calculus by cvenable34
 Find the absolute extrema of the function on the closed interval:$g(x)=2x+5cosx, [0,2pi]$ Maximum: (2Ï, 17.57)Minimum: (2.73, 0.88)
 Grade 12 :: Calculus by ap1111
 $int_1^oo x^3 dx$ True
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