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Author: nsharp1
No. Questions: 3
Created: Sep 25, 2018
Last Modified: 6 years ago

Approximation of Intersection Two Functions

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Simone sketches the functions f(x)=x3+4x2+2x-9 and g(x)=ex-5-7. She sees that one of the intersection points occurs between x=-4 and x=-2. She also notices that, near this intersection point, to the left of the intersection point, f(x) is below g(x) on the graph, and to the right of the intersection point f(x) is above g(x).
Grade 10 Functions and Relations CCSS: HSA-REI.D.11
A.
In order to get a more precise location of the point of intersection, she decides to try the value of x in the middle of the interval. What are the values of each function at this point, rounded to two decimal places?
  1. f(-3)=-6.00,  g(-3)=-7.00
  2. f(-3)=-78.00,  g(-3)=-7.00
  3. f(-3)=-78.00,  g(-3)=-0.39
  4. f(-3)=0.00,  g(-3)=-6.86
Grade 11 Functions and Relations CCSS: HSA-REI.D.11
B.
Given the values of the functions at x=-3, and the relative values of f(x) and g(x) near this point, should Simone choose a value greater than or less than x=-3 to get a more precise value of the point of intersection?
  1. Neither, x=-3 is the point of intersection.
  2. Less than, since f(-3)>g(-3).
  3. Greater than, since f(-3)>g(-3).
  4. Either, since it is still just an approximation.
Grade 11 Functions and Relations CCSS: HSA-REI.D.11
C.
If Simone continues to choose values of x in the middle of each new interval (for example, she would choose x=-2.5 if she looks in the interval -3<x<-2), what would be a reasonable criterion for believing that she has found an accurate point of intersection and why?
  1. |f(x)| is very small, because the x value is very precise.
  2. |g(x)| is very small, since x is near the middle of the interval.
  3. |f(x)+g(x)|2 is near zero, as you've averaged the absolute value of the functions and the functions should cancel each other out.
  4. |f(x)-g(x)| is very small, since these values should be almost equal near the point of intersection.