# Line slope calculator 3x-5y=-13

**Straight line given by points A[4; 5] and B[9; 8]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x+2.6

**Canonical form of the line equation:**3x-5y+13 = 0

**Parametric form of the line equation:**

x = 5t+4

y = 3t+5 ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= -4.3333

**Y intercept:**y

_{0}= q = 2.6

**Distance line from the origin:**d

_{0}= 2.2295

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; 3)

**Normal vector: n =**(3; -5)

**Midpoint of the segment AB: M =**[6.5; 6.5]

**Perpendicular Bisector equation:**5x+3y-52 = 0

**Vector OA = (4; 5) ; |OA| = 6.4031**

**Vector OB = (9; 8) ; |OB| = 12.0416**

**Scalar product OA .OB = 76**

**Angle ∠ AOB = 9°42'24″ = 0.1694 rad**