Trigonometry Question
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For α,β∈ℝ, prove that tan(α+β)=tan(α)+tan(β)1-tan(α)tan(β). Assume that the addition formulas for sine and cosine are known.
Algebraic Steps | Explanation | ||
tan(α)+tan(β)1-tan(α)tan(β) | (R.H.S. of the given equation) | ||
1. | =sin(α)cos(α)+sin(β)cos(β)1-sin(α)cos(α)sin(β)cos(β) | ||
2. | = | Combine fractions in numerator | |
3. | =sin(α)cos(β) + sin(β)cos(α)cos(α)cos(β)cos(α)cos(β)cos(α)cos(β)-sin(α)sin(β)cos(α)cos(β) | ||
4. | =sin(α)cos(β) + sin(β)cos(α)cos(α)cos(β)cos(α)cos(β) - sin(α)sin(β)cos(α)cos(β) | Combine fractions in the denominator | |
5. | = | Division of fractions | |
6. | =sin(α)cos(β)+sin(β)cos(α)cos(α)cos(β)-sin(α)sin(β) | ||
7. | =sin(α+β)cos(α)cos(β)-sin(α)sin(β) | ||
8. | =sin(α+β)cos(α+β) | ||
9. | =tan(α+β) | Definition of tangent | |
Grade 11 Trigonometry CCSS: HSF-TF.C.9
- Definition of tangent
- Pythagorean Identity
- Law of Sines
- αα=1, ββ=1