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Type: Open-Ended
Category: Triangles
Level: Grade 11
Author: nsharp1
Created: 4 years ago

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Triangles Question

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Grade 11 Triangles

The final form of the equation from the previous step should look like h2=4b2c2-(a2-b2-c2)24b2. Using difference of squares and perfect square trinomial formulas, simplify the numerator of this equation. Hint: the difference of squares formula will need to be applied more than once.