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Type: Multiple-Choice
Category: Exponents
Level: Grade 11
Standards: HSF-LE.B.5
Tags: HSF-LE.B.5
Author: HTPhysics
Created: 3 weeks ago

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Grade 11 Exponents CCSS: HSF-LE.B.5

The temperature difference between a cooling object and its surroundings is modeled by [math]D(t) = 80 · (0.5)^(t/20)[/math], where t is in minutes. How long does it take for the temperature difference to halve?
  1. 80 minutes
  2. 10 minutes
  3. 20 minutes
  4. 40 minutes
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