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Solving Exponential Equations Without Logs (Grades 11-12)

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Solving Exponential Equations Without Logs

1. 
Solve. [math]3^{x-1} = 3[/math]
  1. [math]x=2[/math]
  2. [math]x=1[/math]
  3. [math]x=4[/math]
  4. [math]x=0[/math]
 
2. 
What is the solution of [math]6^(x + 1) = 6^(2x - 3)?[/math]
  1. [math]x=0[/math]
  2. [math]x=2[/math]
  3. [math]x=4[/math]
  4. [math]"No solution"[/math]
3. 
Solve.
[math]8^(2x)=4^(x-1)[/math]
  1. [math]x=1/2[/math]
  2. [math]x=2/3[/math]
  3. [math]x=3/5[/math]
  4. [math]x=-1/2[/math]
 
4. 
Solve for x. [math]3^(x+2) = 27[/math]
  1. 3
  2. 1
  3. 2
  4. 9
  5. None of these are correct
5. 
Solve for x. [math]10^(x^2+1) = 100^x[/math]
  1. 4
  2. 3
  3. 2
  4. 1
  5. None of these are correct
 
6. 
Solve for x. [math](4/5)^(x-3) = (25/16)[/math]
  1. [math]-2[/math]
  2. [math]1[/math]
  3. [math]1/2[/math]
  4. [math]0[/math]
  5. none of these are correct
7. 
Solve for x.
[math]root3(16)=8^x[/math]
  1. [math]x=4[/math]
  2. [math]x=7/3[/math]
  3. [math]x=4/9[/math]
  4. [math]x=1/9[/math]
 
8. 
Solve. [math]root[4](8^(5)) = 16^(3x) [/math]
  1. [math]x = 5/12 [/math]
  2. [math]x = 5/16[/math]
  3. [math]x = 15/14 [/math]
  4. [math] x = 5/14 [/math]
9. 
Solve for [math]x[/math]. [math]2^x/8^(x-2) = 16^(3x-2)[/math]
  1. [math] x = 1 [/math]
  2. [math] x = 2/7 [/math]
  3. [math] x = 4/3 [/math]
  4. [math] x = 4/7 [/math]
 
10. 
Solve. [math] (5/3)^(3x-2) = 1 [/math]
  1. [math] x = 2/3 [/math]
  2. [math] x = 1[/math]
  3. [math] x = 0[/math]
  4. [math]"Not possible without logarithms"[/math]
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