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Function and Algebra Concepts Questions - All Grades

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Grade 10 Literal Equations CCSS: HSA-CED.A.4
Solve for [math]B[/math].

[math]A=BC[/math]
  1. [math]B=AC[/math]
  2. [math]B=C/A[/math]
  3. [math]B=A/C[/math]
  4. [math]A=B/C[/math]
Grade 10 Literal Equations CCSS: HSA-CED.A.4
Solve for [math]r[/math].

[math]4x+y=3t-2r[/math]
  1. [math](4x+y-3t)/-2=r[/math]
  2. [math](4x+y-3t)/2=r[/math]
  3. [math](4x+y)/6t=r[/math]
  4. [math]-2(4x+y)/3t=r[/math]
Grade 9 Systems of Equations CCSS: HSA-REI.C.6
There are three ways to solve systems of linear equations. One is graphing. What are the other two?
  1. elimination, substitution
  2. linear combinations, eliminations
  3. eliminations, graphing
  4. substitution, graphing
Grade 9 Quadratic Equations and Expressions CCSS: HSA-REI.B.4, HSA-REI.B.4b
Solve for x.
[math]x^2 + x=12[/math]
  1. 6, -2
  2. -3, -4
  3. -4, 3
  4. -2, 6
Grade 10 Literal Equations CCSS: HSA-CED.A.4
Solve for [math]r[/math].

[math]a=v^2/r[/math]
  1. [math]r=a/v^2[/math]
  2. [math]r=v^2a[/math]
  3. [math]r=v^2/a[/math]
  4. [math]r=sqrt(v)/a[/math]
Grade 9 Inequalities
What is the solution set to the inequality [math]-3x+2>=17[/math] ?
  1. [math]x > -5[/math]
  2. [math]x>=-5[/math]
  3. [math]x<-5[/math]
  4. [math]x<=-5[/math]
Grade 9 Polynomials and Rational Expressions CCSS: HSA-APR.A.1
Add the polynomials.

[math](3x^2+3x+1) + (x^2+x+5)[/math]
  1. [math]4x^2+4x+6[/math]
  2. [math]3x^2-2x+4[/math]
  3. [math]4x^2-4x-6[/math]
  4. [math]2x^2+2x-4[/math]
Grade 9 Systems of Equations CCSS: HSA-REI.C.6
At what point do the lines [math]y = 5x + 2[/math] and [math]y = 6x - 3[/math] intersect?
  1. (-1, 7)
  2. (5, 27)
  3. (8, 14)
  4. (11, -4)
Grade 7 Algebraic Expressions CCSS: 7.EE.A.1
Simplify the following:
2y + 9 + 8y + 7
  1. 26
  2. 10y + 16
  3. 26y
  4. 10y + 9 + 7
Grade 11 Functions and Relations CCSS: HSF-BF.B.4, HSF-BF.B.4a
Find the inverse of the following function. [math]f(x) = 4x^3 + 2[/math]
  1. [math]f^{-1}(x) = (x^3-2)/4[/math]
  2. [math]f^{-1}(x) = (root[3](x) - 2)/4[/math]
  3. [math]f^{-1}(x) = root[3]((x-2)/4) [/math]
  4. [math]f^{-1}(x) = root[3](x-2)/4[/math]
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