Nonlinear Equations and Functions Questions for Tests and Worksheets

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Grade 10 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

Solve for

$y$ .

$(20y-12)/(4y)=4$

$3$
$5$
$2$
$-1$

Grade 10 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

Solve for

$t$ .

$sqrt(5t+11)=6$

$11$
$46/55$
$10$
$5$

Grade 10 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

$(7 - x)/(x - 6) = 0$ if

$x =$

-7
-6
6
7

Grade 10 Nonlinear Equations and Functions

An equation between two variables which, when graphed, does NOT form a straight line.

Linear Equation
Nonlinear Equation
Exponent

Grade 11 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

Solve for all possible values of

$x$ .

$sqrt(x^2+4x-16)=4$

No Solution
$-8, 4$
All real numbers
$-4, 16$

Grade 11 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

Solve for all possible values of

$x$ .

$(sqrt(x+6))/(sqrt(x-2))=(sqrt(4+x))/(sqrt(x-3))$

4, 2
$-4/3$
$3/4$
10

Grade 11 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

Solve for all possible values of

$x$ .

$(3x+6)/(x+2) = x/3$

No Solution
-2, 9
-2, 3
9

Grade 9 Nonlinear Equations and Functions CCSS: HSF-BF.A.1, HSF-BF.A.1a, HSF-LE.B.5

In the year 2000, the population of Virginia was about 7,400,000. Between the years 2000 and 2004, the population in Virginia grew at a rate of 5.4%. At this growth rate, what function gives the population x years after 2000?

$f(x) = 7,400,000 (1 + .054)^x$
$f(x) = 7,400,000 (1 - .054)^x$
$f(x) = 7,400,000 (.054)^x$
$f(x) = 7,400,000x^(.054)$

Grade 9 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

$(2x + 6)/(x - 6) = 3$ if

$x =$

Grade 9 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

Solve the equation

$5/(2x-3)=3/(x+5)$ .

$x=16$
$x=4$
$x=19$
$x=34$

Grade 10 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

Solve for

$x$ .

$(2x-3)/(x-5)=3$

$12$
$21/7$
$2$
$2/3$

Grade 12 Nonlinear Equations and Functions

$(x-4)^2/4 + (y + 6)^2/16 = 1$

The above is an equation of a(n) .

ellipse
hyperbola
circle
parabola

Grade 10 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

Solve for

$x$ .

$sqrt(7x)/x=x/7$

$1$
$1/7$
$7$
$-1$

Grade 9 Nonlinear Equations and Functions

$4x^3 = - 1/54$

$- 1/3$
$- 1/6$
$- 1/9$
$- 1/12$

Grade 9 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

$(10 - x)/(x - 8) = 0$ if

$x =$

-10
-8
8
10

Grade 11 Nonlinear Equations and Functions CCSS: HSG-GPE.A.3

This question is a part of a group with common instructions. View group »

After some more algebra, the equation becomes:

$(c^2-a^2) x^2 - y^2 = (c^2 - a^2) y^2$
What happened to the plus-minus sign that was in the original equation in the seventh question?

Since there are no more square root terms, it is unnecessary.
Each term with it was eventually squared, and a squared term must be positive it.
Because the terms were moved from one side to another multiple times, it is no longer necessary.
Any terms with it canceled out.

Grade 10 Nonlinear Equations and Functions CCSS: HSA-REI.A.2

When a number x is subtracted from 36 and the difference is divided by x, the result is 2. What is the value of x?

Grade 10 Nonlinear Equations and Functions

$4x^3 = - 1/54, x =$

$- 1/3$
$- 1/6$
$- 1/9$
$- 1/12$

Grade 11 Nonlinear Equations and Functions CCSS: HSG-GPE.A.3

This question is a part of a group with common instructions. View group »

After some more algebra, and then moving all terms with

$x$ or

$y$ to the left side of the equation (and all others to the right), the resulting equation is:

$a^2 x^2 - c^2 x^2 + a^2 y^2$	$=$	$a^4 -a^2 c^2$
$(a^2 - c^2)x^2 + a^2 y^2$	$=$	$(a^2 - c^2) a^2$
$b^2 x^2 + a^2 y^2$	$=$	$a^2 b^2$
$x^2 / a^2 + y^2 / b^2$	$=$	$1$

This is the formula for the equation of an ellipse centered at

$(0,0)$ . Why can the substitution

$b^2 = a^2-c^2$ be made?

Since $b$ is undefined so far, it can be defined as any value. Then, using the Pythagorean theorem, $a^2 + b^2 = c^2$ , simply rearrange to solve for $b^2$ .
Knowing that the semi-minor axis is $b$ units long, one can substitute the square of this value for $a^2-c^2$ .
Since $b$ is not yet defined, it can be used to simplify the equation by defining $b^2 = a^2 - c^2$ . A positive value for $a^2-c^2$ exists since $|a| > |c|$ .
Projecting $b$ , the length of the semi-minor axis, onto the semi-major axis it is seen that $b=a-c$ . Then, simply square both sides of the equation.

Grade 10 Nonlinear Equations and Functions

A circle with equation

$(x+4)^2 + (y-3)^2 = 16$ is shifted 5 units to the right. What is the equation of the new circle?

$(x-1)^2+ (y - 3)^2 = 16$
$(x+1)^2+ (y + 3)^2 = 16$
$(x-1)^2+ (y - 8)^2 = 16$
$(x-5)^2+ (y - 5)^2 = 16$

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