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Common Core Standard HSA-CED.A.4 Questions

Rearrange formulas to highlight a quantity of interest, using the same reasoning as in solving equations. For example, rearrange Ohm’s law V = IR to highlight resistance R.

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Grade 9 Literal Equations CCSS: HSA-CED.A.4
Solve for [math]s. -6 = t+5s[/math]
  1. [math]s = -6-t-5[/math]
  2. [math]s = (-6-t)/5[/math]
  3. [math]s = (6+t)/5[/math]
  4. [math]s = -6-5t[/math]
Grade 10 Literal Equations CCSS: HSA-CED.A.4
Solve the equation for the variable indicated.

[math](10ac-x)/11=-3, " for" \ a[/math]
  1. [math]a=(-11+x)/(10c)[/math]
  2. [math]a=(-33+x)/(10c)[/math]
  3. [math]a=10c(-33+x)[/math]
  4. [math]a=(10c)/(33+x)[/math]
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Grade 9 Literal Equations CCSS: HSA-CED.A.4
The formula for the volume of a rectangular prism is [math]V=LWH[/math]. Which equation solves the formula for L?
  1. [math]L=V-WH[/math]
  2. [math]L=V/(HW)[/math]
  3. [math]L=(VW)/H[/math]
  4. [math]L=(VH)/W[/math]
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Solve the equation [math]2a+3b=7(b-c) [/math] for b.
  1. [math](2a-7c)/7=b [/math]
  2. [math](2a+3b+7c)/7=b [/math]
  3. [math](2a+7c)/4=b [/math]
  4. [math] (9a)/4=b[/math]
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Solve for H. [math]V=LWH[/math]
  1. [math]H=V/(LW[/math]
  2. [math]H=V-LW[/math]
  3. [math]H=VLW[/math]
  4. [math]H=(LW)/V[/math]
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Solve the following formula for [math]w[/math].

[math]V=lwh[/math]
  1. [math]w=Vlh[/math]
  2. [math]w=l/(Vh)[/math]
  3. [math]w=V/(lh)[/math]
  4. [math]w=V+l+h[/math]
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Grade 9 Literal Equations CCSS: HSA-CED.A.4
Solve the following formula for [math]l[/math].

[math]V=lwh[/math]
  1. [math]l=Vwh[/math]
  2. [math]l=V/(wh)[/math]
  3. [math]l=(Vw)/h[/math]
  4. [math]l=V+w+h[/math]
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