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Common Core Standard HSF-LE.A.1 Questions

Distinguish between situations that can be modeled with linear functions and with exponential functions.

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Grade 11 Functions and Relations CCSS: HSF-LE.A.1, HSF-LE.A.1a

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One way to restate Proposition A is as follows: "Exponential functions grow by equal factors over equal intervals." What is the value of the equal factors and length of the equal intervals as represented in Proposition A?
  1. Equal factors are [math]x_0[/math], equal intervals are [math]c[/math].
  2. Equal factors are [math]alpha[/math], equal intervals are [math]x[/math].
  3. Equal factors are [math]alpha[/math], equal intervals are [math]c[/math].
  4. Equal factors are [math]c[/math], equal intervals are [math]alpha[/math].
Grade 11 Linear Equations CCSS: HSF-LE.A.1, HSF-LE.A.1a
Given the table below, which lists some of the values of the function [math]f(x)[/math], which of the following is true, and why?

[math] \ \ \ \ \ \ \ \ \ \ \ mathbf{x} \ \ \ \ \ \ \ \ \ \ \ [/math][math] \ \ \ \ \ \ \ \ \ \ \mathbf{f(x)} \ \ \ \ \ \ \ \ \ \ [/math]
[math] 0 [/math][math] -4 [/math]
[math] 2 [/math][math] 2 [/math]
[math] 4 [/math][math] 8 [/math]
[math] 6 [/math][math] 14 [/math]
[math] 8 [/math][math] 20 [/math]
  1. [math]f(x)[/math] is linear, because the difference of y-values over equal intervals is constant.
  2. [math]f(x)[/math] is linear, because the difference of x-values is constantly 2 units.
  3. [math]f(x)[/math] is exponential, because the ratio of y-values over equal intervals is constant.
  4. It cannot be determined whether [math]f(x)[/math] is linear or exponential, because there are no intervals of only one unit in the table.
Grade 11 Linear Equations CCSS: HSF-LE.A.1, HSF-LE.A.1a
Given the table below, which lists some of the values of the function [math]f(x)[/math], which of the following is true, and why?

[math] \ \ \ \ \ \ \ \ \ \ \ mathbf{x} \ \ \ \ \ \ \ \ \ \ \ [/math][math] \ \ \ \ \ \ \ \ \ \ \mathbf{f(x)} \ \ \ \ \ \ \ \ \ \ [/math]
[math] -3 [/math][math] 3/8 [/math]
[math] 0 [/math][math] 3 [/math]
[math] 3 [/math][math] 24 [/math]
[math] 6 [/math][math] 192 [/math]
[math] 7 [/math][math] 384 [/math]
  1. The function is linear, since the difference in most x-values is 3 units.
  2. The function is exponential, since the ratio of y-values, over equal intervals, is constant.
  3. It cannot be determined, since the difference in x-values is not constant.
  4. The function is neither linear nor exponential. Both the difference of y-values and the ratio of y-values are not constant for all the values presented in the table.
Grade 10 Functions and Relations CCSS: HSF-LE.A.1, HSF-LE.A.1a

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What is the value of [math]Delta f = f(x + Delta x) - f(x)[/math], using the definition of [math]f(x) ?[/math] Simplify your answer fully.
  1. [math]m Delta x + 2b[/math]
  2. [math]Delta x - 2b[/math]
  3. [math]m Delta x[/math]
  4. [math]Delta x + 2m[/math]
Grade 10 Functions and Relations CCSS: HSF-LE.A.1, HSF-LE.A.1a

This question is a part of a group with common instructions. View group »

Given the answer in the previous question, which of the following gives the best reasoning as to why one can conclude that a linear function grows by equal differences over equal intervals?
  1. Because the resulting equation for [math]Delta f[/math] is also linear, it will increase at a constant rate.
  2. Because there is no slope in the resulting equation, the value of [math]Delta f[/math] is constant.
  3. Since the resulting equation for [math]Delta f[/math] has no [math]b[/math] value, it is independent of the y-intercept. As such, [math]Delta f[/math] will increase by equal amounts over equal intervals.
  4. Since [math]Delta f[/math] is dependent only on the length of the interval, as long as the interval [math]Delta x[/math] is constant, [math]Delta f[/math] will be the same.
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