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Thermodynamics Questions - All Grades

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College Thermodynamics
Which of the following correctly describes the Second Law of Thermodynamics?
  1. The universe is constantly decreasing in disorder
  2. The entropy in the universe is equal to zero
  3. The universe is constantly increasing in disorder
  4. None of the above
College Thermodynamics
Which of the following can be used to calculate entropy changes in reactions?
  1. ∆Gºreaction=∑nr∆Gºf{reactants}-∑np∆Gºf{products}
  2. ∆Gºreaction=∑nr∆Gºf{reactants}+∑np∆Gºf{products}
  3. ∆Gºreaction=∑np∆Gºf{products}-∑nr∆Gºf{reactants}
  4. None of the above
College Thermodynamics
In addition to what is posited about changes in entropy, according to the Second Law of Thermodynamics, what is happening to energy?
  1. Energy is decreasing
  2. Energy is increasing
  3. Energy is constant
  4. Energy is equal to zero
College Thermodynamics
Which of the following correctly represents when the equilibrium point occurs?
  1. When the value of ∆Gº=1, only
  2. When the value of ∆Gº<0, only
  3. When the value of ∆Gº>0, only
  4. At the lowest value of free energy available to the system
College Thermodynamics
Which of the following correctly describes an increase in entropy?
  1. freezing
  2. crystallization of a solution
  3. dissolving
  4. condensation
College Thermodynamics
Which of the following always result as products of the combustion of fossil fuels?
  1. carbon dioxide and oxygen
  2. carbon, oxygen, and water
  3. carbon dioxide and water
  4. hydrocarbons, only
College Thermodynamics
Which of the following correctly classifies entropy?
  1. It is an intensive property, in that it depends on the identity of the substance
  2. It is an extensive property, in that it depends on the number of moles
  3. It is neither extensive nor intensive
  4. It is an extensive property, in that it depends on the identity of the substance
College Thermodynamics
Which of the following represents ∆Gº, in terms of temperature?
  1. ∆Gº=∆Hº+T∆Sº
  2. ∆Gº=∆Hº-T∆Sº
  3. ∆Gº=∆Hº-T∆Sº
  4. ∆Gº=-∆Hº-T∆Sº
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