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Grade 7 Order of Operations CCSS: 7.NS.A.3
Grade 7 Order of Operations CCSS: 7.NS.A.3
Grade 7 Order of Operations CCSS: 7.NS.A.3
Grade 7 Order of Operations CCSS: 7.NS.A.3
Grade 7 Order of Operations CCSS: 7.EE.B.3
Grade 7 Order of Operations CCSS: 7.NS.A.1, 7.NS.A.1d
(8 x 9)0 + 1=
1. 0
2. 62
3. 63
4. 1
In the equation $5 + (X/4) = 7$, after you add -5 to both sides, you have $(X/4) = 2$ . What is the next step?
1. divide both sides by 4
2. multiply both sides by 4
3. add 4 to both sides
4. subtract 4 to both sides
Grade 7 Order of Operations CCSS: 7.NS.A.3
$4xx6(5xx9) -3$
1. 1203
2. 1077
3. 93
4. -1077
5. -1023
Grade 7 Order of Operations CCSS: 7.EE.B.3
$(5 - 2)^3 + 10 =$
1. $19$
2. $16$
3. $43$
4. $37$
5. None of these
For the following equation, insert parentheses so that the equation is a true statement: $-15-30-:10-15=-9$ .
1. $(-15-30)-:10-15=-9$
2. $-15-(30-:10)-15=-9$
3. $-15-30-:(10-15)=-9$
4. $-15-(30-:10-15)=-9$