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Tenth Grade (Grade 10) Arithmetic and Number Concepts Questions

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Grade 10 Absolute Value
Grade 10 Systems of Equations CCSS: HSA-REI.C.6
Select the solution to the following linear system.
-6y+11x=-36
-4y+7x=-24
  1. y=0,x=-6
  2. y=6,x=0
  3. y=0,x=6
  4. y=-6,x=0
Grade 10 Systems of Equations CCSS: HSA-REI.C.6
Solve the system.

2x+3y=-1
3x+4y=-4
  1. x = -8 and y = 5
  2. x = 8 and y = 5
  3. x = -5 and y = 8
  4. x = -8 and y = -5
Grade 10 Systems of Equations CCSS: HSA-REI.C.6
What is the solution to the system?
y=11x-27
y=7x-11
  1. (4,17)
  2. (-4,-71)
  3. (17,4)
  4. (-71,-4)
  5. none of these are correct
Grade 10 Systems of Equations CCSS: HSA-REI.C.6
Select the solution to the following linear system.
-5x-3y-9=0
4x-18y-54=0
  1. x=-3,y=0
  2. x=0,y=-3
  3. x=3,y=0
  4. x=0,y=3
Grade 10 Systems of Equations CCSS: HSA-REI.C.6
3x+5y=-2
5x+3y=2
  1. x = -1 y = 1
  2. x = 3/5 y = 5/3
  3. x = 1 y = -1
  4. x = 5 y = 3
Grade 10 Systems of Equations
When solving a system of linear equations in two variables by graphing, what does the point of intersection represent? Choose all correct answers.
  1. It shows where the y-values of each equation are equal when the x-values are equal.
  2. It shows the intercepts of each equation.
  3. It shows where the x-values of each equation are equal when the y-values are equal.
  4. It shows a point that satisfies both equations.
Grade 10 Systems of Equations CCSS: HSA-REI.C.6
Which linear system has the solution x = –2 and y = 6?
  1. x + 3y = 16 & 4x + 4y = 16
  2. x + 3y = 17 & 2x + y = 15
  3. x + 2y = –2 & 2x + 4y = –4
  4. 2x + y = –2 & x + y = 16
Grade 10 Literal Equations CCSS: HSA-CED.A.4
Given A=πr2, solve for r.
  1. r=Aπ
  2. r=±Aπ
  3. r=-Aπ
  4. r=Aπ
Grade 10 Systems of Equations CCSS: HSA-REI.C.6
Solve the system of equations.

2x-y+2z=15
-x+y+z=3
3x-y+2z=18
  1. (5,3,1)
  2. (3,1,5)
  3. (-3,5,1)
  4. No Solution
Grade 10 Systems of Equations CCSS: HSA-REI.C.6
Solve by elimination.
3x-6y=12
2x+6y=-12
  1. (-2,-3)
  2. (-2,0)
  3. (0,-2)
  4. (-8,-6)
Grade 10 Systems of Equations CCSS: HSA-CED.A.3, HSA-REI.C.6
Grade 10 Literal Equations CCSS: HSA-CED.A.4
Given V=πr2h, solve for h.
  1. h=Vπr
  2. h=Vπr2
  3. h=Vπr
  4. h=Vπr2
Grade 10 Absolute Value
Solve. |x+1|<-5
  1. x<-6orx>4
  2. x>-6andx<4
  3. All real numbers
  4. No solution
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